unit+4

__**4.1**__

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If you shift the graph to the left it would still have two x-intecepts. ======

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If the lowest point was f(x)=-10, there would be no x intercepts. ======

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In order to have 0 x-intecepts you would have to shift the garph up so the vertex is no longer on the axis. ====== ||

4.3:

**a.)** Explain in your own words why, when solving absolute value equations, it is necessary to create 2 different cases when trying to solve 1 problem. - Absolute value equations have two solutions and the only one to find both solutions is to one make it equal the postive solution and the other equal a negative solution.

**b.)** Explain how there are situations that have 2 solutions (x-intercepts), some that have 1 solution and some that have no soltuions. Be sure to reference the graphical representations in your binder to help you explain how each situation [|varies]. **-** When there are situations with 2 solutions for the xintercepts this means that the /\ or \/ shape crosses the x intercept line twice.

4.4:

__**WITHOUT SOLVING**__... explain the reasoning you would use to determine which absolute value graph matches the inequality. Remember to write your explanation in your wikispace.


 * |2x+4|-5>7 matches with graph C. **This is because it is an **or** inequality.


 * [[image:mhsalgebra2cp/4.4_journal.jpg caption="4.4_journal.jpg"]] ||