unit+3

__ 3.1: __
1.) X>-2 would match graphical representation D.)

2.) x < -2 would match the graphical representation A.)

3.) -2 < X __<__ (line under) 2 would match graphical representation C.)

4.) x __>__ //2 or x < - 2 would match graphicaol represtentation E.)//

5.)//-2 __<__ x __<__ 2 would match graphical represtentation F.)//

6.) x > 2 or x __<__ -2 would match graphical represtentation B.)

=
-The process I used to match each inequality to its correct statement was for the first one I looked for a close circle on the -2 with the arrow pointing to the right. The second inequality I looked for an open circle over the -2 with the arrow pointing to the left. The third inequality I looked for an open circle on -2 and a closed circle on 2 and a line shaded in between them. The fourth inequality i looked for an arrow pointing to the left with a open circle on the -2 and an arrow pointing to the right with a closed circle. The fifth inequality i looked for a closed circle on the -2 and a closed circle on the 2 and a line shaded in between them. The sixth inequality i looked for an arrow pointing to the left with a closed circle on the -2 and an arrow pointing to the right with an open circle. I narrowed down my choices by looking at which statements were And inequalities and which ones were OR inequalities. =====

__ 3.3: __
Y<-1/2x+4

__ **3.4:** __
==(4, 5) is a solution because it is the purple reigion meaning it's an answer for the system. And (3, 1) is a solution to g(x) because it is in the red shaded reigion meaning it's a solution for only that inequality. To test a point, I would create a system either a positive or negative slope, depending on where I want it to cross.==